Question
Easy

Value of $tan\{cos^{-1}(-\frac{2}{7})-\frac{\pi}{2}\}$ is:

1
$\frac{2}{3\sqrt{5}}$
2
$\frac{2}{3}$
3
$\frac{1}{\sqrt{5}}$
4
$\frac{4}{5}$
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 3
Chapter: Sets, Relations and Functions
Topic: Inverse Trigonometric Functions
Correct Answer
Option A
Explanation

To solve the problem and justify why Option 1 is correct, we need to evaluate the expression \( \tan\left(\cos^{-1}\left(-\frac{2}{7}\right) - \frac{\pi}{2}\right) \). ### Step-by-step Explanation: 1. Understanding \(\cos^{-1}\left(-\frac{2}{7}\right)\): - The expression \(\cos^{-1}\left(-\frac{2}{7}\right)\) represents an angle \(\theta\) such that \(\cos(\theta) = -\frac{2}{7}\). - In a right triangle, if \(\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\), then here, the adjacent side is \(-2\) and the hypotenuse is \(7\). 2. Finding the opposite side: - Using the…Read More

Value of tancos1frac27fracpi2 is - HTET Level 3 | Clear Cutoff