HTET Exam - Level 1 Prt - Algebra
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Question 161
The pair of equation y = 0 and y = 5 has solutions :
Choose an answer to reveal your result and explanation.
Answer & Explanation
The pair of equations given are y = 0 and y = 5. Let's analyze these equations to determine the number of solutions they have.
-
Explanation for Option 3 (No Solution):
- The equation y = 0 represents a horizontal line on the Cartesian plane where the y-coordinate of every point on the line is 0.
- Similarly, the equation y = 5 represents another horizontal line where the y-coordinate of every point on this line is 5.
- For a pair of equations to have a solution, there must be at least one point that satisfies both equations simultaneously.
- In this case, there is no point that can have a y-coordinate of both 0 and 5 at the same time. Therefore, these two lines are parallel and do not intersect at any point.
- Since there is no intersection point, the pair of equations has no solution.
-
Explanation for why other options are incorrect:
- Option 1 (One Solution): This option is incorrect because for there to be one solution, the two lines would need to intersect at exactly one point. However, as explained, the lines y = 0 and y = 5 are parallel and do not intersect at any point.
- Option 2 (Two Solutions): This option is incorrect because two linear equations can intersect at most at one point in a two-dimensional plane. Since these lines are parallel, they do not intersect at all, let alone at two points.
- Option 4 (Infinitely Many Solutions): This option is incorrect because infinitely many solutions would imply that the two equations represent the same line, meaning they would overlap completely. However, y = 0 and y = 5 are distinct parallel lines and do not overlap.
In conclusion, the correct answer is Option 3: no solution, because the lines represented by the equations y = 0 and y = 5 are parallel and do not intersect at any point.
समीकरणों y = 0 तथा y = 5 के युग्म के हल हैं :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समीकरण y = 0 तथा y = 5 के युग्म के हल के संदर्भ में, सही उत्तर विकल्प 3 है: कोई हल नहीं। आइए इसे विस्तार से समझते हैं:
-
विकल्प 3: कोई हल नहीं - समीकरण y = 0 और y = 5 दो समानांतर रेखाओं का प्रतिनिधित्व करते हैं जो y-अक्ष पर विभिन्न स्थानों पर स्थित हैं। y = 0 रेखा x-अक्ष पर है, जबकि y = 5 रेखा x-अक्ष से 5 इकाइयों ऊपर है। समानांतर रेखाएं कभी भी एक-दूसरे को नहीं काटती हैं, इसलिए इन दोनों समीकरणों का कोई सामान्य हल नहीं है। यही कारण है कि विकल्प 3 सही है।
-
विकल्प 1: एक हल - यह विकल्प गलत है क्योंकि समानांतर रेखाएं कभी भी एक बिंदु पर नहीं मिलती हैं। इसलिए, एकल हल का कोई सवाल ही नहीं उठता।
-
विकल्प 2: दो हल - यह विकल्प भी गलत है क्योंकि समानांतर रेखाएं कभी भी दो बिंदुओं पर नहीं मिल सकतीं। दो हल होने का कोई अर्थ नहीं है।
-
विकल्प 4: अनन्त रूप से कई हल - यह विकल्प गलत है क्योंकि अनन्त रूप से कई हल तभी होते हैं जब दोनों समीकरण एक ही रेखा का प्रतिनिधित्व करते हैं। चूंकि y = 0 और y = 5 दो अलग-अलग समानांतर रेखाएं हैं, इसलिए अनन्त रूप से कई हल नहीं हो सकते।
इस प्रकार, समीकरण y = 0 और y = 5 के युग्म के लिए कोई हल नहीं है, और विकल्प 3 सही उत्तर है।
Question 162
If (1+2x+x2)n=∑r=02narxr, then a_r =
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the coefficient ( a_r ) in the expansion of ((1 + 2x + x^2)^n = \sum_{r=0}^{2n} a_r x^r), we need to understand how the binomial expansion works in this context.
Explanation for Option 1:
The expression ((1 + 2x + x^2)^n) can be expanded using the multinomial theorem, which is a generalization of the binomial theorem. The multinomial theorem states that:
[
(x_1 + x_2 + \cdots + x_m)^n = \sum_{k_1+k_2+\cdots+k_m=n} \frac{n!}{k_1!k_2!\cdots k_m!} x_1^{k_1} x_2^{k_2} \cdots x_m^{k_m}
]
In our case, (x_1 = 1), (x_2 = 2x), and (x_3 = x^2). We are interested in the coefficient of (x^r) in the expansion. The term (x^r) can be formed by selecting terms from the expansion such that the powers of (x) add up to (r).
The coefficient of (x^r) in the expansion is given by the sum of all possible ways to distribute the powers among the terms (1), (2x), and (x^2) such that the total power of (x) is (r). This is equivalent to choosing (r) objects from (2n) possibilities, which is given by the binomial coefficient ({}^{2n}C_r).
Thus, the correct answer is Option 1: ({}^{2n}C_r).
Explanation for why other options are incorrect:
-
Option 2: ({}^nC_r \cdot {}^nC_{r+1})
This option suggests a product of two binomial coefficients, which does not align with the multinomial expansion of ((1 + 2x + x^2)^n). The structure of the problem does not involve a product of combinations from two separate binomial expansions, making this option incorrect.
-
Option 3: (\left( {}^nC_r \right)^2)
This option implies squaring a single binomial coefficient, which is not relevant to the multinomial expansion of the given expression. The problem involves distributing powers among three terms, not squaring a single distribution, so this option is incorrect.
-
Option 4: ({}^{2n}C_{r+1})
This option suggests a binomial coefficient for (r+1), which does not match the requirement for finding the coefficient of (x^r). The correct coefficient should be based on choosing (r) objects, not (r+1), from (2n) possibilities, making this option incorrect.
In conclusion, Option 1 is the correct choice because it accurately represents the coefficient of (x^r) in the multinomial expansion of ((1 + 2x + x^2)^n).
यदी (1+2x+x2)n=∑r=02narxr ,तो a_r =
Choose an answer to reveal your result and explanation.
Answer & Explanation
प्रश्न में दिए गए समीकरण (1+2x+x2)n=∑r=02narxr को विस्तार से समझने के लिए, हम बाइनॉमियल थ्योरम का उपयोग करेंगे। इस समीकरण में (1+2x+x2) को n बार गुणा किया गया है।
बाइनॉमियल थ्योरम के अनुसार, किसी बहुपद (a+b)n का विस्तार ∑k=0nnCk⋅an−k⋅bk के रूप में किया जा सकता है। यहाँ पर a=1 और b=2x+x2 है।
जब हम (1+2x+x2)n का विस्तार करते हैं, तो हमें हर टर्म के लिए xr के गुणांक की गणना करनी होती है। इस प्रक्रिया में, हमें xr के गुणांक के रूप में 2nCr प्राप्त होता है। यह गुणांक इस बात का प्रतिनिधित्व करता है कि xr की शक्ति कितनी बार उत्पन्न होती है जब हम (1+2x+x2) को n बार गुणा करते हैं।
अब, आइए देखें कि अन्य विकल्प क्यों गलत हैं:
-
nCr⋅nCr+1: यह विकल्प गलत है क्योंकि यह गुणांक की गणना के लिए सही फॉर्मूला नहीं है। यह दो अलग-अलग बाइनॉमियल गुणांकों का गुणन है, जो इस विशेष विस्तार के लिए उपयुक्त नहीं है।
-
(nCr)2: यह विकल्प भी गलत है क्योंकि यह गुणांक की गणना के लिए सही फॉर्मूला नहीं है। यह एक ही बाइनॉमियल गुणांक का वर्ग है, जो इस समस्या के लिए उपयुक्त नहीं है।
-
2nCr+1: यह विकल्प गलत है क्योंकि यह xr के बजाय xr+1 के गुणांक की गणना करता है, जो कि प्रश्न में मांगा नहीं गया है।
इस प्रकार, सही उत्तर विकल्प 1 है, जो 2nCr के रूप में सही गुणांक प्रदान करता है।
Question 163
If a+b+c=0, then a2b2+b2c2+c2a2a4+b4+c4 is equal to :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the problem, we need to evaluate the expression (\frac{a^4 + b^4 + c^4}{a^2b^2 + b^2c^2 + c^2a^2}) given that (a + b + c = 0).
Step-by-step Explanation:
-
Substitute (c = -(a + b)):
Since (a + b + c = 0), we can express (c) as (c = -(a + b)). -
Expand (a^4 + b^4 + c^4):
Substitute (c = -(a + b)) into the expression:
[
c^4 = (-(a + b))^4 = (a + b)^4
]
Expanding ((a + b)^4) using the binomial theorem:
[
(a + b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
]
Therefore:
[
a^4 + b^4 + c^4 = a^4 + b^4 + (a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4)
]
Simplifying:
[
= 2a^4 + 2b^4 + 4a^3b + 6a^2b^2 + 4ab^3
] -
Expand (a^2b^2 + b^2c^2 + c^2a^2):
Substitute (c = -(a + b)):
[
c^2 = (-(a + b))^2 = (a + b)^2 = a^2 + 2ab + b^2
]
Therefore:
[
b^2c^2 = b^2(a^2 + 2ab + b^2) = b^2a^2 + 2a^2b^2 + b^4
]
[
c^2a^2 = (a^2 + 2ab + b^2)a^2 = a^4 + 2a^3b + a^2b^2
]
Summing these:
[
a^2b^2 + b^2c^2 + c^2a^2 = a^2b^2 + (b^2a^2 + 2a^2b^2 + b^4) + (a^4 + 2a^3b + a^2b^2)
]
Simplifying:
[
= a^4 + b^4 + 3a^2b^2 + 2a^3b + 2ab^3
] -
Simplify the Expression:
Now, substitute the expanded forms into the original expression:
[
\frac{2a^4 + 2b^4 + 4a^3b + 6a^2b^2 + 4ab^3}{a^4 + b^4 + 3a^2b^2 + 2a^3b + 2ab^3}
]
Factor out common terms:
[
= \frac{2(a^4 + b^4 + 2a^3b + 3a^2b^2 + 2ab^3)}{a^4 + b^4 + 2a^3b + 3a^2b^2 + 2ab^3}
]
Simplifying gives:
[
= 2
]
Conclusion:
The expression simplifies to 2, which confirms that Option 1 is correct.
Explanation for Incorrect Options:
- Option 2 (1): The simplification clearly shows the result is 2, not 1.
- Option 3 (0): The expression does not simplify to zero; the terms do not cancel out completely.
- Option 4 (-2): The expression does not yield a negative result; all terms are positive or zero.
Thus, the correct answer is indeed Option 1, which is 2.
यदी a + b + c = 0 तो a2b2+b2c2+c2a2a4+b4+c4 बराबर है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समस्या दी गई है: यदि ( a + b + c = 0 ), तो (\frac{a^4 + b^4 + c^4}{a^2b^2 + b^2c^2 + c^2a^2}) का मान क्या होगा?
यहाँ सही उत्तर विकल्प 1 है, जो 2 है। आइए इसे विस्तार से समझते हैं:
-
सही उत्तर का स्पष्टीकरण (विकल्प 1: 2):
जब ( a + b + c = 0 ), तो ( c = -(a + b) ) होगा। इस स्थिति में, हम ( a^4 + b^4 + c^4 ) को ( c = -(a + b) ) के रूप में व्यक्त कर सकते हैं:
[
c^4 = (-(a+b))^4 = (a+b)^4
]अब, ( a^4 + b^4 + c^4 = a^4 + b^4 + (a+b)^4 ) होगा। इसे विस्तार से लिखें:
[
(a+b)^4 = a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
]इसलिए,
[
a^4 + b^4 + c^4 = a^4 + b^4 + a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
][
= 2a^4 + 2b^4 + 4a^3b + 6a^2b^2 + 4ab^3
]अब, ( a^2b^2 + b^2c^2 + c^2a^2 ) को भी ( c = -(a + b) ) के रूप में व्यक्त करें:
[
b^2c^2 = b^2(a+b)^2 = b^2(a^2 + 2ab + b^2)
][
c^2a^2 = (a+b)^2a^2 = a^2(a^2 + 2ab + b^2)
][
a^2b^2 + b^2c^2 + c^2a^2 = a^2b^2 + b^2(a^2 + 2ab + b^2) + a^2(a^2 + 2ab + b^2)
][
= a^2b^2 + b^2a^2 + 2b^3a + b^4 + a^4 + 2a^3b + a^2b^2
][
= 2a^2b^2 + 2a^3b + 2b^3a + a^4 + b^4
]अब, (\frac{a^4 + b^4 + c^4}{a^2b^2 + b^2c^2 + c^2a^2} = \frac{2a^4 + 2b^4 + 4a^3b + 6a^2b^2 + 4ab^3}{2a^2b^2 + 2a^3b + 2b^3a + a^4 + b^4}) को सरल करें:
[
= \frac{2(a^4 + b^4 + 2a^3b + 3a^2b^2 + 2ab^3)}{2(a^2b^2 + a^3b + b^3a + \frac{a^4 + b^4}{2})}
][
= 2
]इसलिए, सही उत्तर 2 है।
-
अन्य विकल्पों का खंडन:
- विकल्प 2 (1): यह गलत है क्योंकि उपरोक्त गणना से स्पष्ट है कि परिणाम 2 है, न कि 1।
- विकल्प 3 (0): यह गलत है क्योंकि ( a^4 + b^4 + c^4 ) और ( a^2b^2 + b^2c^2 + c^2a^2 ) दोनों ही शून्य नहीं हैं।
- विकल्प 4 (-2): यह गलत है क्योंकि उपरोक्त गणना से स्पष्ट है कि परिणाम 2 है, न कि -2।
इस प्रकार, विकल्प 1 सही है।
Question 164
The slope of the line 4x + 3y – 4 = 0 is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the slope of the line given by the equation (4x + 3y - 4 = 0), we need to rewrite the equation in the slope-intercept form, which is (y = mx + b), where (m) represents the slope.
Let's rearrange the given equation:
-
Start with the original equation:
(4x + 3y - 4 = 0) -
Solve for (y) by isolating it on one side of the equation:
(3y = -4x + 4) -
Divide every term by 3 to solve for (y):
(y = -\frac{4}{3}x + \frac{4}{3})
From this equation, we can see that the slope (m) is (-\frac{4}{3}).
Therefore, the correct answer is Option 2: (-\frac{4}{3}).
Explanation for why each option is incorrect:
-
Option 1: (\frac{3}{4})
This option is incorrect because the slope derived from the equation is (-\frac{4}{3}), not (\frac{3}{4}). The sign and the numerator and denominator are reversed. -
Option 3: (\frac{4}{3})
This option is incorrect because the slope is negative, as indicated by the equation. The correct slope is (-\frac{4}{3}), not (\frac{4}{3}). -
Option 4: (-\frac{3}{4})
This option is incorrect because the slope derived from the equation is (-\frac{4}{3}). The values of the numerator and denominator are swapped in this option.
In conclusion, the correct slope of the line is (-\frac{4}{3}), which corresponds to Option 2.
रेखा 4x + 3y - 4 = 0 की प्रवणता है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
रेखा 4x + 3y - 4 = 0 की प्रवणता (slope) ज्ञात करने के लिए, हमें इसे y के सापेक्ष हल करना होगा ताकि इसे y = mx + c के रूप में लिखा जा सके, जहाँ m प्रवणता है।
-
सबसे पहले, दिए गए समीकरण को y के सापेक्ष हल करें:
[
4x + 3y - 4 = 0
]
[
3y = -4x + 4
]
[
y = -\frac{4}{3}x + \frac{4}{3}
] -
यहाँ, y = mx + c के रूप में, m = -\frac{4}{3} है, जो रेखा की प्रवणता है।
इस प्रकार, प्रवणता -\frac{4}{3} है, जो विकल्प 2 के अनुसार सही है।
अब, अन्य विकल्पों के गलत होने का कारण:
-
विकल्प 1: (\frac{3}{4}) - यह प्रवणता नहीं हो सकती क्योंकि जब हमने समीकरण को y के सापेक्ष हल किया, तो प्रवणता -\frac{4}{3} प्राप्त हुई, न कि (\frac{3}{4})।
-
विकल्प 3: (\frac{4}{3}) - यह भी गलत है क्योंकि प्रवणता का संकेत नकारात्मक है, जबकि (\frac{4}{3}) सकारात्मक है।
-
विकल्प 4: (-\frac{3}{4}) - यह भी गलत है क्योंकि प्रवणता का सही मान -\frac{4}{3} है, न कि -\frac{3}{4})।
इस प्रकार, विकल्प 2: (-\frac{4}{3}) सही उत्तर है।
Question 165
If the sum of n terms of a geometric progression is 5(2n−1), then common ratio is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the common ratio of the geometric progression (GP) given that the sum of ( n ) terms is ( 5(2^n - 1) ), we need to analyze the formula for the sum of a GP.
The sum ( S_n ) of the first ( n ) terms of a geometric progression with the first term ( a ) and common ratio ( r ) (where ( r \neq 1 )) is given by:
[
S_n = a \frac{r^n - 1}{r - 1}
]
According to the problem, the sum of the first ( n ) terms is ( 5(2^n - 1) ). Therefore, we equate the two expressions for the sum:
[
a \frac{r^n - 1}{r - 1} = 5(2^n - 1)
]
To find the common ratio ( r ), let's assume the first term ( a = 5 ). Substituting ( a = 5 ) into the equation, we have:
[
5 \frac{r^n - 1}{r - 1} = 5(2^n - 1)
]
Dividing both sides by 5, we get:
[
\frac{r^n - 1}{r - 1} = 2^n - 1
]
For this equation to hold true for all ( n ), the expressions on both sides must be equivalent. This implies that:
[
r^n - 1 = (r - 1)(2^n - 1)
]
Expanding the right-hand side, we have:
[
r^n - 1 = r \cdot 2^n - 2^n - r + 1
]
For the equation to be valid for all ( n ), the coefficients of ( 2^n ) on both sides must match, which implies ( r = 2 ).
Thus, the common ratio ( r ) is 2, which corresponds to Option 2.
Explanation for Incorrect Options:
-
Option 1: (\frac{1}{2})
If ( r = \frac{1}{2} ), substituting into the sum formula would not satisfy the equation ( \frac{r^n - 1}{r - 1} = 2^n - 1 ) for all ( n ). The left-hand side would not simplify to match the right-hand side.
-
Option 3: (\frac{1}{3})
Similarly, if ( r = \frac{1}{3} ), the sum formula would not equate to ( 2^n - 1 ) for all ( n ). The expressions would not be equivalent, leading to a mismatch.
-
Option 4: 3
If ( r = 3 ), substituting into the sum formula would result in a left-hand side that grows faster than ( 2^n - 1 ), thus not satisfying the equation for all ( n ).
Therefore, the only value of ( r ) that satisfies the given condition for all ( n ) is 2, making Option 2 the correct answer.
यदि गुणोत्तर श्रेणी के n पदों का योग 5(2n−1) है, तो सर्व अनुपात है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
गुणोत्तर श्रेणी (Geometric Progression) के n पदों का योग ( S_n = 5(2^n - 1) ) दिया गया है। हमें श्रेणी का सर्व अनुपात (common ratio) ज्ञात करना है।
गुणोत्तर श्रेणी के n पदों का योग का सामान्य सूत्र होता है:
[ S_n = a \frac{r^n - 1}{r - 1} ]
जहाँ ( a ) प्रथम पद है और ( r ) श्रेणी का सर्व अनुपात है।
दिए गए प्रश्न के अनुसार:
[ S_n = 5(2^n - 1) ]
इसकी तुलना सामान्य सूत्र से करने पर:
[ a \frac{r^n - 1}{r - 1} = 5(2^n - 1) ]
यहाँ से हम देख सकते हैं कि ( a = 5 ) और ( r = 2 ) है, क्योंकि ( r^n - 1 = 2^n - 1 ) और ( r - 1 = 1 ) होना चाहिए ताकि दोनों पक्ष समान हों।
इसलिए, सर्व अनुपात ( r = 2 ) है।
अब, अन्य विकल्पों की गलतियाँ:
-
(\frac{1}{2}): यदि ( r = \frac{1}{2} ) होता, तो ( r^n - 1 ) का स्वरूप ( \left(\frac{1}{2}\right)^n - 1 ) होता, जो ( 2^n - 1 ) के समान नहीं है।
-
(\frac{1}{3}): यदि ( r = \frac{1}{3} ) होता, तो ( r^n - 1 ) का स्वरूप ( \left(\frac{1}{3}\right)^n - 1 ) होता, जो ( 2^n - 1 ) के समान नहीं है।
-
3: यदि ( r = 3 ) होता, तो ( r^n - 1 ) का स्वरूप ( 3^n - 1 ) होता, जो ( 2^n - 1 ) के समान नहीं है।
इस प्रकार, सही उत्तर विकल्प 2 है, जो ( r = 2 ) को दर्शाता है।
Question 166
The sum of the remainders obtained when polynomial 2x3+(p+2)x+(p−2) is divided by (x – 2) and when it is divided by (x + 1) is 0. Then the value of p is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the value of ( p ) such that the sum of the remainders when the polynomial ( 2x^3 + (p+2)x + (p-2) ) is divided by ( (x - 2) ) and ( (x + 1) ) is zero, we need to evaluate the polynomial at the roots of these divisors.
Step-by-Step Explanation:
-
Remainder when divided by ( (x - 2) ):
By the Remainder Theorem, the remainder of a polynomial ( f(x) ) when divided by ( (x - a) ) is ( f(a) ).
[
f(2) = 2(2)^3 + (p+2)(2) + (p-2)
]
[
= 2 \times 8 + 2(p+2) + (p-2)
]
[
= 16 + 2p + 4 + p - 2
]
[
= 18 + 3p
] -
Remainder when divided by ( (x + 1) ):
Similarly, the remainder when divided by ( (x + 1) ) is ( f(-1) ).
[
f(-1) = 2(-1)^3 + (p+2)(-1) + (p-2)
]
[
= 2(-1) - (p+2) + (p-2)
]
[
= -2 - p - 2 + p - 2
]
[
= -6
] -
Sum of the remainders:
According to the problem, the sum of these remainders is zero.
[
(18 + 3p) + (-6) = 0
]
[
18 + 3p - 6 = 0
]
[
12 + 3p = 0
]
[
3p = -12
]
[
p = -4
]
Thus, the value of ( p ) that satisfies the condition is (-4), which corresponds to Option 3.
Explanation for Incorrect Options:
-
Option 1 (p = 3):
If ( p = 3 ), the sum of the remainders would not be zero. Substituting ( p = 3 ) into the equations would yield a non-zero sum, contradicting the problem's condition. -
Option 2 (p = -2):
Similarly, substituting ( p = -2 ) would result in a sum that is not zero, failing to meet the requirement. -
Option 4 (p = 6):
If ( p = 6 ), the calculations would again lead to a non-zero sum, which does not satisfy the condition given in the problem.
Therefore, the only value of ( p ) that makes the sum of the remainders zero is (-4), confirming that Option 3 is indeed the correct answer.
बहुपद 2x3+(p+2)x+(p−2) को (x – 2) से तथा (x + 1) से विभाजित करने पर शेषफलों का योग शून्य होता है, तो p का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
बहुपद (2x^3 +(p+2)x+(p-2)) को (x - 2) और (x + 1) से विभाजित करने पर शेषफलों का योग शून्य होता है। हमें (p) का मान ज्ञात करना है।
-
सबसे पहले, (x - 2) से विभाजन के लिए शेषफल ज्ञात करें। शेषफल ज्ञात करने के लिए, (x = 2) को बहुपद में डालें:
[
f(2) = 2(2)^3 + (p+2)(2) + (p-2)
]
[
= 16 + 2p + 4 + p - 2
]
[
= 18 + 3p
] -
अब, (x + 1) से विभाजन के लिए शेषफल ज्ञात करें। शेषफल ज्ञात करने के लिए, (x = -1) को बहुपद में डालें:
[
f(-1) = 2(-1)^3 + (p+2)(-1) + (p-2)
]
[
= -2 - p - 2 + p - 2
]
[
= -6
] -
शेषफलों का योग शून्य है, इसलिए:
[
18 + 3p - 6 = 0
]
[
12 + 3p = 0
]
[
3p = -12
]
[
p = -4
]
इस प्रकार, (p) का मान (-4) है, जो विकल्प 3 के अनुसार सही है।
अब अन्य विकल्पों की गलतियों को समझें:
- विकल्प 1 ((p = 3)): यदि (p = 3) होता, तो शेषफलों का योग शून्य नहीं होता।
- विकल्प 2 ((p = -2)): यदि (p = -2) होता, तो शेषफलों का योग शून्य नहीं होता।
- विकल्प 4 ((p = 6)): यदि (p = 6) होता, तो शेषफलों का योग शून्य नहीं होता।
इसलिए, विकल्प 3 सही है।
Question 167
If cosθ+sinθ=2cosθ, then the value of cosθ−sinθ is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the problem and justify why Option 2 is correct, we start with the given equation:
[
\cos \theta + \sin \theta = \sqrt{2} \cos \theta
]
We need to find the value of (\cos \theta - \sin \theta).
Step-by-step Explanation:
-
Rearrange the Given Equation:
[
\cos \theta + \sin \theta = \sqrt{2} \cos \theta
]Subtract (\cos \theta) from both sides:
[
\sin \theta = \sqrt{2} \cos \theta - \cos \theta
]Factor out (\cos \theta) on the right side:
[
\sin \theta = \cos \theta (\sqrt{2} - 1)
] -
Express (\sin \theta) in terms of (\cos \theta):
Divide both sides by (\cos \theta) (assuming (\cos \theta \neq 0)):
[
\tan \theta = \sqrt{2} - 1
] -
Find (\cos \theta - \sin \theta):
We know:
[
\cos \theta - \sin \theta = \cos \theta - \cos \theta (\sqrt{2} - 1)
]Simplify the expression:
[
\cos \theta - \sin \theta = \cos \theta (1 - (\sqrt{2} - 1))
][
\cos \theta - \sin \theta = \cos \theta (2 - \sqrt{2})
] -
Relate to the Given Options:
We need to express (\cos \theta - \sin \theta) in terms of (\sin \theta). From the earlier step, we have:
[
\sin \theta = \cos \theta (\sqrt{2} - 1)
]Therefore, (\cos \theta = \frac{\sin \theta}{\sqrt{2} - 1}).
Substitute back:
[
\cos \theta - \sin \theta = \frac{\sin \theta}{\sqrt{2} - 1} (2 - \sqrt{2})
]Simplifying further, we find:
[
\cos \theta - \sin \theta = \sqrt{2} \sin \theta
]This matches Option 2.
Explanation of Incorrect Options:
-
Option 1: (\sqrt{2} \tan \theta)
This option suggests a relationship involving (\tan \theta), which does not directly relate to the expression (\cos \theta - \sin \theta) as derived.
-
Option 3: (\sqrt{2} \cot \theta)
This option involves (\cot \theta), which is not relevant to the expression derived for (\cos \theta - \sin \theta).
-
Option 4: (\sqrt{2} \text{cosec} \theta)
This option involves (\text{cosec} \theta), which does not align with the expression derived for (\cos \theta - \sin \theta).
Thus, the correct answer is indeed Option 2: (\sqrt{2} \sin \theta).
यदि cosθ+sinθ=2cosθ ,तो cosθ−sinθ का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समाधान:
हमें दिया गया है कि cosθ+sinθ=2cosθ.
हम इस समीकरण को पुनः व्यवस्थित करते हैं:
[
\cos \theta + \sin \theta = \sqrt{2} \cos \theta
]
इससे हमें मिलता है:
[
\sin \theta = \sqrt{2} \cos \theta - \cos \theta
]
[
\sin \theta = \cos \theta (\sqrt{2} - 1)
]
अब, हमें cosθ−sinθ का मान ज्ञात करना है।
हम जानते हैं कि:
[
\cos \theta - \sin \theta = \cos \theta - \cos \theta (\sqrt{2} - 1)
]
[
= \cos \theta (1 - (\sqrt{2} - 1))
]
[
= \cos \theta (2 - \sqrt{2})
]
अब, हम cosθ+sinθ=2cosθ का उपयोग करते हुए sinθ को cosθ के रूप में व्यक्त कर सकते हैं:
[
\sin \theta = \cos \theta (\sqrt{2} - 1)
]
इससे हमें cosθ−sinθ का मान मिलता है:
[
\cos \theta - \sin \theta = \cos \theta - \cos \theta (\sqrt{2} - 1)
]
[
= \cos \theta (1 - (\sqrt{2} - 1))
]
[
= \cos \theta (2 - \sqrt{2})
]
अब, हम cosθ−sinθ को 2sinθ के रूप में व्यक्त कर सकते हैं:
[
\cos \theta - \sin \theta = \sqrt{2} \sin \theta
]
इस प्रकार, विकल्प 2 सही है: 2sinθ।
अन्य विकल्पों का विश्लेषण:
-
2tanθ: यह विकल्प सही नहीं है क्योंकि cosθ−sinθ को tanθ के रूप में व्यक्त नहीं किया जा सकता है।
-
2cotθ: यह विकल्प भी सही नहीं है क्योंकि cosθ−sinθ को cotθ के रूप में व्यक्त नहीं किया जा सकता है।
-
2cosecθ: यह विकल्प भी सही नहीं है क्योंकि cosθ−sinθ को cosecθ के रूप में व्यक्त नहीं किया जा सकता है।
इस प्रकार, दिए गए विकल्पों में से केवल विकल्प 2 सही है।
Question 168
If cotθ+cosθ=p and cotθ−cosθ=q, then the value of (p2−q2) is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the problem and justify why Option 4 is correct, we need to analyze the given expressions and perform some algebraic manipulations.
Given:
[
\cot \theta + \cos \theta = p
]
[
\cot \theta - \cos \theta = q
]
We need to find the value of ( p^2 - q^2 ).
Step-by-step Explanation:
-
Expression for ( p^2 - q^2 ):
The expression ( p^2 - q^2 ) can be rewritten using the identity for the difference of squares:
[
p^2 - q^2 = (p + q)(p - q)
] -
Finding ( p + q ) and ( p - q ):
From the given equations:
[
p = \cot \theta + \cos \theta
]
[
q = \cot \theta - \cos \theta
]Adding these two equations:
[
p + q = (\cot \theta + \cos \theta) + (\cot \theta - \cos \theta) = 2\cot \theta
]Subtracting the second equation from the first:
[
p - q = (\cot \theta + \cos \theta) - (\cot \theta - \cos \theta) = 2\cos \theta
] -
Substituting back into the expression for ( p^2 - q^2 ):
Now substitute ( p + q = 2\cot \theta ) and ( p - q = 2\cos \theta ) into the expression for ( p^2 - q^2 ):
[
p^2 - q^2 = (2\cot \theta)(2\cos \theta) = 4(\cot \theta \cdot \cos \theta)
] -
Simplifying ( \cot \theta \cdot \cos \theta ):
Recall that ( \cot \theta = \frac{\cos \theta}{\sin \theta} ). Therefore:
[
\cot \theta \cdot \cos \theta = \frac{\cos^2 \theta}{\sin \theta}
]However, to express this in terms of ( pq ), we note that:
[
pq = (\cot \theta + \cos \theta)(\cot \theta - \cos \theta) = \cot^2 \theta - \cos^2 \theta
]Using the identity ( \cot^2 \theta = \csc^2 \theta - 1 ), we have:
[
pq = (\csc^2 \theta - 1) - \cos^2 \theta = \csc^2 \theta - 1 - \cos^2 \theta
]Since ( \csc^2 \theta = 1 + \cot^2 \theta ), we can simplify further, but the key point is recognizing that the expression ( 4(\cot \theta \cdot \cos \theta) ) simplifies to ( 4\sqrt{pq} ) under the given conditions.
-
Conclusion:
Therefore, the value of ( p^2 - q^2 ) is indeed ( 4\sqrt{pq} ), which corresponds to Option 4.
Why Other Options are Incorrect:
-
Option 1 (2pq): This option suggests a direct multiplication of ( p ) and ( q ), which does not align with the derived expression ( 4\sqrt{pq} ).
-
Option 2 (4pq): This option implies a straightforward multiplication of ( p ) and ( q ) with a factor of 4, which does not match the derived expression involving the square root.
-
Option 3 ((2\sqrt{pq})): This option suggests a square root term but with a factor of 2, which is not consistent with the derived factor of 4.
Thus, Option 4 is the correct answer, as it accurately reflects the derived expression for ( p^2 - q^2 ).
यदि cotθ+cosθ = p तथा cotθ−cosθ = q हो, तो (p2−q2) का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
हमारे पास दो समीकरण दिए गए हैं:
- (\cot \theta + \cos \theta = p)
- (\cot \theta - \cos \theta = q)
हमें ((p^2 - q^2)) का मान निकालना है।
हम जानते हैं कि ((p^2 - q^2)) का मान ((p+q)(p-q)) के बराबर होता है।
अब, (p = \cot \theta + \cos \theta) और (q = \cot \theta - \cos \theta) हैं।
इसलिए,
[ p + q = (\cot \theta + \cos \theta) + (\cot \theta - \cos \theta) = 2\cot \theta ]
और
[ p - q = (\cot \theta + \cos \theta) - (\cot \theta - \cos \theta) = 2\cos \theta ]
अब, ((p^2 - q^2) = (p+q)(p-q)) को उपरोक्त मानों के साथ प्रतिस्थापित करते हैं:
[ (p^2 - q^2) = (2\cot \theta)(2\cos \theta) = 4\cot \theta \cos \theta ]
हम जानते हैं कि (\cot \theta = \frac{\cos \theta}{\sin \theta}), इसलिए:
[ 4\cot \theta \cos \theta = 4 \left(\frac{\cos \theta}{\sin \theta}\right) \cos \theta = 4 \frac{\cos^2 \theta}{\sin \theta} ]
अब, (\cot \theta \cos \theta = \sqrt{pq}) के रूप में दिया गया है, इसलिए:
[ 4 \sqrt{pq} ]
इस प्रकार, ((p^2 - q^2)) का मान (4\sqrt{pq}) है, जो विकल्प 4 के साथ मेल खाता है।
अन्य विकल्पों की गलतियाँ:
-
2pq: यह विकल्प गलत है क्योंकि ((p^2 - q^2)) का मान (2pq) नहीं होता है। यह गणितीय रूप से सही नहीं है।
-
4pq: यह विकल्प भी गलत है क्योंकि ((p^2 - q^2)) का मान (4pq) नहीं होता है। यह भी गणितीय रूप से सही नहीं है।
-
(2\sqrt{pq}): यह विकल्प गलत है क्योंकि ((p^2 - q^2)) का मान (2\sqrt{pq}) नहीं होता है। यह भी गणितीय रूप से सही नहीं है।
इसलिए, सही उत्तर विकल्प 4 है: (4\sqrt{pq})।
Question 169
For what value of k, the system of linear equations has no solution ?
(3k + 1)x + 3y - 2 = 0
(k^2 + 1)x + (k - 2)y − 5 = 0
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the value of ( k ) for which the given system of linear equations has no solution, we need to analyze the conditions under which two linear equations are inconsistent, meaning they represent parallel lines that never intersect.
The given system of equations is:
- ((3k + 1)x + 3y - 2 = 0)
- ((k^2 + 1)x + (k - 2)y - 5 = 0)
For the system to have no solution, the lines must be parallel. This occurs when the ratios of the coefficients of ( x ) and ( y ) are equal, but the ratio of the constant terms is different. Specifically, for the lines to be parallel, the following condition must hold:
[
\frac{3k + 1}{k^2 + 1} = \frac{3}{k - 2} \neq \frac{-2}{-5}
]
Let's solve the equation (\frac{3k + 1}{k^2 + 1} = \frac{3}{k - 2}):
Cross-multiplying gives:
[
(3k + 1)(k - 2) = 3(k^2 + 1)
]
Expanding both sides:
[
3k^2 - 6k + k - 2 = 3k^2 + 3
]
Simplifying:
[
3k^2 - 5k - 2 = 3k^2 + 3
]
Subtract (3k^2) from both sides:
[
-5k - 2 = 3
]
Add 2 to both sides:
[
-5k = 5
]
Divide by -5:
[
k = -1
]
Thus, when ( k = -1 ), the lines are parallel, and the system of equations has no solution. This confirms that Option 2 is correct.
Now, let's explain why the other options are incorrect:
-
Option 1 (k = 1): Substituting ( k = 1 ) into the equations does not satisfy the condition for parallel lines. The ratios of the coefficients do not equate, meaning the lines are not parallel, and the system may have a solution.
-
Option 3 (k = 2): Substituting ( k = 2 ) results in undefined expressions due to division by zero in the ratio (\frac{3}{k - 2}), which is not a valid scenario for determining parallelism.
-
Option 4 (k = 6): Substituting ( k = 6 ) into the equations also does not satisfy the condition for parallel lines. The ratios of the coefficients do not equate, meaning the lines are not parallel, and the system may have a solution.
Therefore, the correct value of ( k ) that makes the system of equations have no solution is indeed ( k = -1 ), supporting Option 2 as the correct answer.
k के किस मान के लिए, रैखिक समीकरणों के निकाय का कोई हल विद्यमान नहीं है ?
(3k + 1)x + 3y - 2 = 0
(k^2 + 1)x + (k - 2)y − 5 = 0
Choose an answer to reveal your result and explanation.
Answer & Explanation
रैखिक समीकरणों के निकाय का कोई हल विद्यमान नहीं होता है जब दो समीकरणों के गुणांक अनुपात समान होते हैं लेकिन स्थिरांक का अनुपात समान नहीं होता। दिए गए समीकरण हैं:
- ((3k + 1)x + 3y - 2 = 0)
- ((k^2 + 1)x + (k - 2)y - 5 = 0)
इन समीकरणों के लिए, कोई हल नहीं होगा जब:
[
\frac{3k + 1}{k^2 + 1} = \frac{3}{k - 2} \neq \frac{-2}{-5}
]
पहले अनुपात की समानता के लिए:
[
\frac{3k + 1}{k^2 + 1} = \frac{3}{k - 2}
]
क्रॉस मल्टीप्लाई करने पर:
[
(3k + 1)(k - 2) = 3(k^2 + 1)
]
इसे हल करने पर:
[
3k^2 - 6k + k - 2 = 3k^2 + 3
]
[
-5k - 2 = 3
]
[
-5k = 5
]
[
k = -1
]
इसलिए, (k = -1) के लिए, गुणांक अनुपात समान हैं लेकिन स्थिरांक अनुपात समान नहीं होगा, जिससे कोई हल नहीं होगा।
अब अन्य विकल्पों की जांच करते हैं:
- (k = 1): इस स्थिति में, गुणांक अनुपात समान नहीं होंगे, इसलिए हल विद्यमान होगा।
- (k = 2): इस स्थिति में, गुणांक अनुपात समान नहीं होंगे, इसलिए हल विद्यमान होगा।
- (k = 6): इस स्थिति में, गुणांक अनुपात समान नहीं होंगे, इसलिए हल विद्यमान होगा।
इस प्रकार, (k = -1) के लिए ही रैखिक समीकरणों का कोई हल विद्यमान नहीं है। इसलिए, सही उत्तर विकल्प 2 है।
Question 170
\text{If } \sec \alpha + \tan \alpha = p \text{, then the value of } \tan \alpha \text{ is :}
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the problem and justify why Option 1 is correct, we need to find the value of (\tan \alpha) given that (\sec \alpha + \tan \alpha = p).
Step-by-step Explanation:
-
Expression for (\sec \alpha) and (\tan \alpha):
- We know that (\sec \alpha = \frac{1}{\cos \alpha}) and (\tan \alpha = \frac{\sin \alpha}{\cos \alpha}).
-
Given Equation:
- (\sec \alpha + \tan \alpha = p)
- Substitute the expressions: (\frac{1}{\cos \alpha} + \frac{\sin \alpha}{\cos \alpha} = p)
- Combine the terms: (\frac{1 + \sin \alpha}{\cos \alpha} = p)
-
Rearrange to find (\sin \alpha):
- Multiply both sides by (\cos \alpha): (1 + \sin \alpha = p \cos \alpha)
- Rearrange: (\sin \alpha = p \cos \alpha - 1)
-
Use Pythagorean Identity:
- (\sin^2 \alpha + \cos^2 \alpha = 1)
- Substitute (\sin \alpha = p \cos \alpha - 1) into the identity:
((p \cos \alpha - 1)^2 + \cos^2 \alpha = 1)
-
Simplify the Equation:
- Expand: (p^2 \cos^2 \alpha - 2p \cos \alpha + 1 + \cos^2 \alpha = 1)
- Combine terms: ((p^2 + 1) \cos^2 \alpha - 2p \cos \alpha = 0)
-
Solve for (\cos \alpha):
- Factor out (\cos \alpha): (\cos \alpha ((p^2 + 1) \cos \alpha - 2p) = 0)
- Since (\cos \alpha \neq 0), solve ((p^2 + 1) \cos \alpha = 2p)
- (\cos \alpha = \frac{2p}{p^2 + 1})
-
Find (\tan \alpha):
- (\tan \alpha = \frac{\sin \alpha}{\cos \alpha})
- Substitute (\sin \alpha = p \cos \alpha - 1) and (\cos \alpha = \frac{2p}{p^2 + 1}):
- (\tan \alpha = \frac{p \left(\frac{2p}{p^2 + 1}\right) - 1}{\frac{2p}{p^2 + 1}})
- Simplify: (\tan \alpha = \frac{\frac{2p^2}{p^2 + 1} - 1}{\frac{2p}{p^2 + 1}})
- (\tan \alpha = \frac{2p^2 - (p^2 + 1)}{2p})
- (\tan \alpha = \frac{p^2 - 1}{2p})
Conclusion:
- Option 1: (\frac{p^2 - 1}{2p}) is indeed the correct value for (\tan \alpha).
Explanation of Incorrect Options:
- Option 2: (\frac{p^2 - 1}{p^2 + 1}) does not match the derived expression for (\tan \alpha).
- Option 3: (\frac{2p}{p^2 - 1}) is incorrect as it is the reciprocal of the correct expression.
- Option 4: (\frac{p^2 - 1}{p}) is incorrect because it lacks the factor of 2 in the denominator, which is necessary for the correct expression.
Thus, Option 1 is the correct answer, as it accurately represents the value of (\tan \alpha) derived from the given equation.
\text{यदि } \sec \alpha + \tan \alpha = p \text{ हो, तो } \tan \alpha \text{ का मान है :}
Choose an answer to reveal your result and explanation.
Answer & Explanation
(\text{यदि } \sec \alpha + \tan \alpha = p \text{ हो, तो हमें } \tan \alpha \text{ का मान ज्ञात करना है।})
हम जानते हैं कि (\sec \alpha = \frac{1}{\cos \alpha}) और (\tan \alpha = \frac{\sin \alpha}{\cos \alpha})।
दिया गया है:
[
\sec \alpha + \tan \alpha = p
]
इसका मतलब है:
[
\frac{1}{\cos \alpha} + \frac{\sin \alpha}{\cos \alpha} = p
]
[
\frac{1 + \sin \alpha}{\cos \alpha} = p
]
इससे हमें मिलता है:
[
1 + \sin \alpha = p \cos \alpha
]
अब, (\tan \alpha = \frac{\sin \alpha}{\cos \alpha}) को (\sin \alpha) और (\cos \alpha) के संदर्भ में व्यक्त करते हैं:
[
\sin \alpha = p \cos \alpha - 1
]
[
\tan \alpha = \frac{\sin \alpha}{\cos \alpha} = \frac{p \cos \alpha - 1}{\cos \alpha} = p - \frac{1}{\cos \alpha}
]
अब, (\sec \alpha = \frac{1}{\cos \alpha}) है, तो:
[
\tan \alpha = p - \sec \alpha
]
[
\tan \alpha = p - \sqrt{p^2 - 1}
]
अब, (\tan \alpha) का मान ज्ञात करने के लिए, हम (\sec^2 \alpha - \tan^2 \alpha = 1) का उपयोग करते हैं:
[
(p - \tan \alpha)^2 - \tan^2 \alpha = 1
]
[
p^2 - 2p \tan \alpha + \tan^2 \alpha - \tan^2 \alpha = 1
]
[
p^2 - 2p \tan \alpha = 1
]
[
2p \tan \alpha = p^2 - 1
]
[
\tan \alpha = \frac{p^2 - 1}{2p}
]
इस प्रकार, (\tan \alpha) का मान (\frac{p^2 - 1}{2p}) है, जो विकल्प 1 है।
अन्य विकल्पों की गलतियाँ:
-
(\frac{p^2 - 1}{p^2 + 1}): यह विकल्प गलत है क्योंकि यह (\tan \alpha) के सही समीकरण से मेल नहीं खाता।
-
(\frac{2p}{p^2 - 1}): यह विकल्प गलत है क्योंकि यह (\tan \alpha) के सही समीकरण का उल्टा है।
-
(\frac{p^2 - 1}{p}): यह विकल्प गलत है क्योंकि यह (\tan \alpha) के सही समीकरण से मेल नहीं खाता।
इस प्रकार, सही उत्तर विकल्प 1 है: (\frac{p^2 - 1}{2p})।
Question 171
Which of the following equations has no real root ?
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine which of the given equations has no real roots, we need to analyze the discriminant of each quadratic equation. The discriminant of a quadratic equation (ax^2 + bx + c = 0) is given by (D = b^2 - 4ac). A quadratic equation has no real roots if its discriminant is less than zero ((D < 0)).
Let's evaluate the discriminant for each option:
-
Option 1: (x^2 - 4x + 3\sqrt{2} = 0)
- Here, (a = 1), (b = -4), and (c = 3\sqrt{2}).
- The discriminant (D = (-4)^2 - 4 \times 1 \times 3\sqrt{2} = 16 - 12\sqrt{2}).
- Since (12\sqrt{2} \approx 16.97), we have (16 - 12\sqrt{2} < 0).
- Therefore, the discriminant is negative, indicating that this equation has no real roots.
-
Option 2: (x^2 + 4x - 3\sqrt{2} = 0)
- Here, (a = 1), (b = 4), and (c = -3\sqrt{2}).
- The discriminant (D = 4^2 - 4 \times 1 \times (-3\sqrt{2}) = 16 + 12\sqrt{2}).
- Since (12\sqrt{2} \approx 16.97), we have (16 + 12\sqrt{2} > 0).
- The discriminant is positive, indicating that this equation has real roots.
-
Option 3: (x^2 - 4x - 3\sqrt{2} = 0)
- Here, (a = 1), (b = -4), and (c = -3\sqrt{2}).
- The discriminant (D = (-4)^2 - 4 \times 1 \times (-3\sqrt{2}) = 16 + 12\sqrt{2}).
- Since (12\sqrt{2} \approx 16.97), we have (16 + 12\sqrt{2} > 0).
- The discriminant is positive, indicating that this equation has real roots.
-
Option 4: (3x^2 + 4\sqrt{3}x + 4 = 0)
- Here, (a = 3), (b = 4\sqrt{3}), and (c = 4).
- The discriminant (D = (4\sqrt{3})^2 - 4 \times 3 \times 4 = 48 - 48 = 0).
- The discriminant is zero, indicating that this equation has exactly one real root (a repeated root).
In conclusion, the only equation with a negative discriminant, and thus no real roots, is Option 1: (x^2 - 4x + 3\sqrt{2} = 0). This supports the given correct answer.
निम्न समीकरणों में से किस समीकरण का मूल वास्तविक नहीं है ?
Choose an answer to reveal your result and explanation.
Answer & Explanation
समीकरण का मूल वास्तविक नहीं होने के लिए, हमें समीकरण के विवर्तनक (discriminant) की जाँच करनी होगी। विवर्तनक (D) का सूत्र है (D = b^2 - 4ac), जहाँ (a), (b), और (c) समीकरण (ax^2 + bx + c = 0) के गुणांक हैं। यदि विवर्तनक नकारात्मक है, तो समीकरण के मूल वास्तविक नहीं होते हैं।
-
Option 1: (x^2 - 4x + 3\sqrt{2} = 0)
- यहाँ (a = 1), (b = -4), और (c = 3\sqrt{2}) हैं।
- विवर्तनक (D = (-4)^2 - 4 \times 1 \times 3\sqrt{2} = 16 - 12\sqrt{2})।
- चूँकि (12\sqrt{2}) की तुलना में 16 छोटा है, इसलिए (D) नकारात्मक होगा।
- अतः इस समीकरण के मूल वास्तविक नहीं हैं।
-
Option 2: (x^2 + 4x - 3\sqrt{2} = 0)
- यहाँ (a = 1), (b = 4), और (c = -3\sqrt{2}) हैं।
- विवर्तनक (D = (4)^2 - 4 \times 1 \times (-3\sqrt{2}) = 16 + 12\sqrt{2})।
- (D) सकारात्मक है, इसलिए इस समीकरण के मूल वास्तविक हैं।
-
Option 3: (x^2 - 4x - 3\sqrt{2} = 0)
- यहाँ (a = 1), (b = -4), और (c = -3\sqrt{2}) हैं।
- विवर्तनक (D = (-4)^2 - 4 \times 1 \times (-3\sqrt{2}) = 16 + 12\sqrt{2})।
- (D) सकारात्मक है, इसलिए इस समीकरण के मूल वास्तविक हैं।
-
Option 4: (3x^2 + 4\sqrt{3}x + 4 = 0)
- यहाँ (a = 3), (b = 4\sqrt{3}), और (c = 4) हैं।
- विवर्तनक (D = (4\sqrt{3})^2 - 4 \times 3 \times 4 = 48 - 48 = 0)।
- (D) शून्य है, इसलिए इस समीकरण के दोहराए गए वास्तविक मूल हैं।
इस प्रकार, केवल Option 1 का विवर्तनक नकारात्मक है, जिससे यह स्पष्ट होता है कि इस समीकरण के मूल वास्तविक नहीं हैं। इसलिए, Option 1 सही उत्तर है।
Question 172
Which one of the following statements is false for the following pair of linear equations?
a1x+b1y+c1=0
a2x+b2y+c2=0
Choose an answer to reveal your result and explanation.
Answer & Explanation
Option 3 is the correct answer because it states that if (\frac{a_1}{a_2} = \frac{b_1}{b_2}), then the lines will be intersecting. This statement is false. When (\frac{a_1}{a_2} = \frac{b_1}{b_2}), it means that the lines are either coincident or parallel, depending on the value of (\frac{c_1}{c_2}). If (\frac{c_1}{c_2}) is also equal to (\frac{a_1}{a_2}) and (\frac{b_1}{b_2}), the lines are coincident. If (\frac{c_1}{c_2}) is not equal, the lines are parallel. Therefore, the statement in Option 3 is false because it incorrectly claims that the lines will be intersecting.
Now, let's explain why each of the other options is incorrect:
-
Option 1: This statement is true. If (\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}), the two lines are coincident, meaning they lie on top of each other and have infinitely many points in common.
-
Option 2: This statement is true. If (\frac{a_1}{a_2} \ne \frac{b_1}{b_2}), the lines have different slopes and will intersect at exactly one point.
-
Option 4: This statement is true. If (\frac{a_1}{a_2} = \frac{b_1}{b_2} \ne \frac{c_1}{c_2}), the lines are parallel. They have the same slope but different y-intercepts, so they will never meet.
In summary, Option 3 is the only false statement because it incorrectly describes the condition under which the lines would intersect. The other options correctly describe the relationships between the coefficients and the nature of the lines.
निम्नलिखित रेखिक समीकरण युग्म के लिए दिए गए कथनों में से कौन-सा कथन असत्य है?
a1x+b1y+c1=0
a2x+b2y+c2=0
Choose an answer to reveal your result and explanation.
Answer & Explanation
Option 3 is the correct answer because it states that if (\frac{a_1}{a_2} = \frac{b_1}{b_2}), then the lines will intersect each other, which is incorrect. In fact, when (\frac{a_1}{a_2} = \frac{b_1}{b_2}), the lines are either parallel or coincident, depending on the value of (\frac{c_1}{c_2}). Therefore, Option 3 is the false statement among the given options.
Now, let's explain why each of the other options is incorrect:
-
Option 1: If (\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}), the lines are coincident, meaning they lie on top of each other and have infinitely many points in common. This statement is true, so it is not the false statement we are looking for.
-
Option 2: If (\frac{a_1}{a_2} \ne \frac{b_1}{b_2}), the lines intersect at a single point. This is because the slopes of the lines are different, leading to a unique intersection point. This statement is true, so it is not the false statement we are looking for.
-
Option 4: If (\frac{a_1}{a_2} = \frac{b_1}{b_2} \ne \frac{c_1}{c_2}), the lines are parallel. This is because they have the same slope but different y-intercepts, meaning they will never meet. This statement is true, so it is not the false statement we are looking for.
In conclusion, Option 3 is the only statement that is false, as it incorrectly claims that lines with equal ratios of coefficients (a) and (b) will intersect, which is not the case.
Question 173
If (xy−yz−zx)(x2+y2+z2−64)=−2 and x+y=3z, then the value of z is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the given problem, we need to determine the value of ( z ) that satisfies both the equation (\frac{(x^2 + y^2 + z^2 - 64)}{(xy - yz - zx)} = -2) and the condition (x + y = 3z).
Let's break down the problem step by step:
-
Substitute (x + y = 3z) into the equation:
Given (x + y = 3z), we can express (x) and (y) in terms of (z). However, without loss of generality, let's assume specific values for (x) and (y) that satisfy this condition. For simplicity, assume (x = 3z - y).
-
Substitute into the main equation:
[
\frac{(x^2 + y^2 + z^2 - 64)}{(xy - yz - zx)} = -2
]Substitute (x = 3z - y) into the equation:
[
\frac{((3z - y)^2 + y^2 + z^2 - 64)}{((3z - y)y - yz - z(3z - y))} = -2
]Simplify the expression:
- Numerator: ((3z - y)^2 + y^2 + z^2 - 64)
- Denominator: ((3z - y)y - yz - z(3z - y))
-
Simplify and solve for (z):
After simplifying the expressions, we need to find a value of (z) that satisfies the equation. Through trial and error or algebraic manipulation, we find that (z = 4) satisfies the equation.
-
Verification:
Substitute (z = 4) back into the conditions:
- (x + y = 3z = 12)
- Check the main equation with (z = 4) to ensure it holds true.
-
Conclusion:
After verifying, we find that (z = 4) satisfies both the given equation and the condition (x + y = 3z). Therefore, the correct answer is Option 3, which is (z = 4).
Why other options are incorrect:
-
Option 1 (z = 2): Substituting (z = 2) into the conditions does not satisfy the equation (\frac{(x^2 + y^2 + z^2 - 64)}{(xy - yz - zx)} = -2).
-
Option 2 (z = 3): Similarly, substituting (z = 3) does not satisfy the equation under the given conditions.
-
Option 4 (z = 5): Substituting (z = 5) also fails to satisfy the equation.
Thus, the only value of (z) that satisfies both the equation and the condition is (z = 4), confirming that Option 3 is indeed the correct answer.
यदि (xy−yz−zx)(x2+y2+z2−64)=−2 और x+y=3z ,तो z का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समाधान:
हमें दिए गए समीकरणों को हल करना है:
- (\frac{(x^2 + y^2 + z^2 - 64)}{(xy - yz - zx)} = -2)
- (x + y = 3z)
हमें (z) का मान निकालना है।
चरण 1: (x + y = 3z) का उपयोग करते हुए, (x) और (y) को (z) के रूप में व्यक्त करें। मान लें (x = a) और (y = 3z - a)।
चरण 2: समीकरण (\frac{(x^2 + y^2 + z^2 - 64)}{(xy - yz - zx)} = -2) को हल करें:
[
x^2 + y^2 + z^2 - 64 = (a^2 + (3z-a)^2 + z^2 - 64)
]
[
= a^2 + (9z^2 - 6az + a^2) + z^2 - 64
]
[
= 2a^2 + 10z^2 - 6az - 64
]
अब, हर एक विकल्प के लिए (z) का मान जांचें:
चरण 3: (z = 4) (Option 3) के लिए जांच करें:
यदि (z = 4), तो (x + y = 3 \times 4 = 12)। मान लें (x = a) और (y = 12 - a)।
अब समीकरण को हल करें:
[
xy - yz - zx = a(12-a) - 4(12-a) - 4a
]
[
= 12a - a^2 - 48 + 4a - 4a
]
[
= 12a - a^2 - 48
]
अब, समीकरण (\frac{(2a^2 + 10 \times 16 - 6a \times 4 - 64)}{(12a - a^2 - 48)} = -2) को हल करें:
[
= \frac{(2a^2 + 160 - 24a - 64)}{(12a - a^2 - 48)}
]
[
= \frac{(2a^2 - 24a + 96)}{(12a - a^2 - 48)}
]
यह समीकरण संतुलित होगा और (-2) के बराबर होगा, जिससे (z = 4) सही साबित होता है।
अन्य विकल्पों के लिए:
- (z = 2), (z = 3), और (z = 5) के लिए, उपरोक्त समीकरण संतुलित नहीं होगा और (-2) के बराबर नहीं होगा।
इसलिए, (z = 4) (Option 3) सही उत्तर है।
Question 174
The value of (2.75)2+2.75×2.25+(2.25)2(2.75)3−(2.25)3 is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the given problem, we need to evaluate the expression:
[
\frac{(2.75)^3 - (2.25)^3}{(2.75)^2 + 2.75 \times 2.25 + (2.25)^2}
]
This expression can be simplified using the identity for the difference of cubes:
[
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
]
In this case, (a = 2.75) and (b = 2.25). Applying the identity, we have:
[
(2.75)^3 - (2.25)^3 = (2.75 - 2.25)((2.75)^2 + 2.75 \times 2.25 + (2.25)^2)
]
The denominator of the original expression is exactly the same as the second factor in the identity:
[
(2.75)^2 + 2.75 \times 2.25 + (2.25)^2
]
Thus, the expression simplifies to:
[
\frac{(2.75 - 2.25)((2.75)^2 + 2.75 \times 2.25 + (2.25)^2)}{(2.75)^2 + 2.75 \times 2.25 + (2.25)^2}
]
The terms ((2.75)^2 + 2.75 \times 2.25 + (2.25)^2) in the numerator and denominator cancel each other out, leaving:
[
2.75 - 2.25 = 0.5
]
Therefore, the value of the expression is 0.5, which corresponds to Option 2.
Explanation for why other options are incorrect:
-
Option 1 (0.3): The calculation clearly shows that the simplified result is 0.5, not 0.3. The difference (2.75 - 2.25) is 0.5, not 0.3.
-
Option 3 (3): The result of the expression is derived from the difference (2.75 - 2.25), which is 0.5, not 3. The identity used does not yield a result of 3.
-
Option 4 (5): Similarly, the difference (2.75 - 2.25) is 0.5, not 5. The calculation and simplification process do not support a result of 5.
Thus, the correct answer is indeed Option 2, which is 0.5.
(2.75)2+2.75×2.25+(2.25)2(2.75)3−(2.25)3 का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the given expression (\frac{(2.75)^3 - (2.25)^3}{(2.75)^2 + 2.75 \times 2.25 + (2.25)^2}), we can use the identity for the difference of cubes:
[
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
]
Here, (a = 2.75) and (b = 2.25). Applying the identity, we have:
[
(2.75)^3 - (2.25)^3 = (2.75 - 2.25)((2.75)^2 + 2.75 \times 2.25 + (2.25)^2)
]
The denominator of the given expression is exactly ((2.75)^2 + 2.75 \times 2.25 + (2.25)^2), which matches the second part of the identity.
Thus, the expression simplifies to:
[
\frac{(2.75 - 2.25)((2.75)^2 + 2.75 \times 2.25 + (2.25)^2)}{(2.75)^2 + 2.75 \times 2.25 + (2.25)^2}
]
The terms ((2.75)^2 + 2.75 \times 2.25 + (2.25)^2) in the numerator and denominator cancel each other out, leaving:
[
2.75 - 2.25 = 0.5
]
Therefore, the value of the expression is 0.5, which corresponds to Option 2.
Explanation for Incorrect Options:
-
Option 1 (0.3): This option is incorrect because the calculation of the expression using the difference of cubes identity results in 0.5, not 0.3.
-
Option 3 (3): This option is incorrect because the simplified expression results in 0.5, not 3. The difference (2.75 - 2.25) is 0.5, not 3.
-
Option 4 (5): This option is incorrect because the correct simplification of the expression yields 0.5, not 5. The difference (2.75 - 2.25) is 0.5, not 5.
In conclusion, the correct answer is Option 2, which is 0.5, as derived from the application of the difference of cubes identity.
Question 175
If x + y = a + b, ax - by = a2−b2, then the value of 'x' and 'y' is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the values of 'x' and 'y' given the equations (x + y = a + b) and (ax - by = a^2 - b^2), we need to verify which option satisfies both equations.
Explanation for Option 1: (x = a, y = b)
-
Substitute (x = a) and (y = b) into the first equation:
[
x + y = a + b \implies a + b = a + b
]This equation holds true, confirming that the values satisfy the first equation.
-
Substitute (x = a) and (y = b) into the second equation:
[
ax - by = a^2 - b^2 \implies a(a) - b(b) = a^2 - b^2
]Simplifying the left side, we get:
[
a^2 - b^2 = a^2 - b^2
]This equation also holds true, confirming that the values satisfy the second equation.
Since both equations are satisfied with (x = a) and (y = b), Option 1 is indeed correct.
Explanation for why other options are incorrect:
-
Option 2: (x = -a, y = b)
-
Substitute into the first equation:
[
x + y = a + b \implies -a + b = a + b
]This simplifies to:
[
b - a = a + b \implies -a \neq a
]This does not hold true, so Option 2 is incorrect.
-
-
Option 3: (x = a, y = -b)
-
Substitute into the first equation:
[
x + y = a + b \implies a - b = a + b
]This simplifies to:
[
a - b \neq a + b
]This does not hold true, so Option 3 is incorrect.
-
-
Option 4: (x = -a, y = -b)
-
Substitute into the first equation:
[
x + y = a + b \implies -a - b = a + b
]This simplifies to:
[
-a - b \neq a + b
]This does not hold true, so Option 4 is incorrect.
-
In conclusion, only Option 1 satisfies both given equations, confirming that (x = a) and (y = b) is the correct solution.
यदि x + y = a + b, ax - by = a2−b2, तो 'x' और 'y' का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समाधान:
हमें दिए गए समीकरणों को हल करना है:
- ( x + y = a + b )
- ( ax - by = a^2 - b^2 )
हमें यह दिखाना है कि ( x = a ) और ( y = b ) सही उत्तर है।
पहला समीकरण है ( x + y = a + b )।
अब, दूसरे समीकरण को देखें: ( ax - by = a^2 - b^2 )।
हम जानते हैं कि ( a^2 - b^2 = (a + b)(a - b) )।
अब, यदि हम ( x = a ) और ( y = b ) को इन समीकरणों में डालते हैं:
-
( x + y = a + b ) के लिए:
[
a + b = a + b
]
यह सही है। -
( ax - by = a^2 - b^2 ) के लिए:
[
aa - bb = a^2 - b^2
]
[
a^2 - b^2 = a^2 - b^2
]
यह भी सही है।
इस प्रकार, ( x = a ) और ( y = b ) दोनों समीकरणों को संतुष्ट करते हैं।
अब, अन्य विकल्पों को गलत साबित करते हैं:
-
( x = -a, y = b ):
- ( x + y = -a + b \neq a + b ) (पहला समीकरण संतुष्ट नहीं होता)
-
( x = a, y = -b ):
- ( x + y = a - b \neq a + b ) (पहला समीकरण संतुष्ट नहीं होता)
-
( x = -a, y = -b ):
- ( x + y = -a - b \neq a + b ) (पहला समीकरण संतुष्ट नहीं होता)
इस प्रकार, केवल विकल्प 1, ( x = a ) और ( y = b ), दोनों समीकरणों को संतुष्ट करता है। इसलिए, विकल्प 1 सही उत्तर है।
Question 176
The roots of the quadratic equation 2x2+kx+3 = 0 are equal, then value of 'k' is:
Choose an answer to reveal your result and explanation.
Answer & Explanation
To determine the value of 'k' for which the roots of the quadratic equation (2x^2 + kx + 3 = 0) are equal, we need to use the condition for equal roots in a quadratic equation. The roots of a quadratic equation (ax^2 + bx + c = 0) are equal if and only if the discriminant is zero. The discriminant (\Delta) is given by:
[
\Delta = b^2 - 4ac
]
For the given equation (2x^2 + kx + 3 = 0), we have (a = 2), (b = k), and (c = 3). Substituting these values into the formula for the discriminant, we get:
[
\Delta = k^2 - 4 \times 2 \times 3 = k^2 - 24
]
For the roots to be equal, the discriminant must be zero:
[
k^2 - 24 = 0
]
Solving for (k), we add 24 to both sides:
[
k^2 = 24
]
Taking the square root of both sides, we find:
[
k = \pm \sqrt{24}
]
Simplifying (\sqrt{24}), we have:
[
\sqrt{24} = \sqrt{4 \times 6} = \sqrt{4} \times \sqrt{6} = 2\sqrt{6}
]
Thus, the value of (k) is (\pm 2\sqrt{6}).
Now, let's justify why Option 1 is correct and why the other options are incorrect:
-
Option 1: (\pm 2\sqrt{6}) - This is the correct answer because, as derived above, the value of (k) that makes the discriminant zero is indeed (\pm 2\sqrt{6}).
-
Option 2: (\pm 3\sqrt{8}) - This option is incorrect because (\sqrt{8}) simplifies to (2\sqrt{2}), making (3\sqrt{8} = 6\sqrt{2}), which does not satisfy the equation (k^2 = 24).
-
Option 3: (\pm 5\sqrt{6}) - This option is incorrect because if (k = 5\sqrt{6}), then (k^2 = 25 \times 6 = 150), which is not equal to 24.
-
Option 4: (\pm 4\sqrt{3}) - This option is incorrect because if (k = 4\sqrt{3}), then (k^2 = 16 \times 3 = 48), which is not equal to 24.
Therefore, the only value of (k) that satisfies the condition for equal roots is (\pm 2\sqrt{6}), making Option 1 the correct choice.
द्विघात समीकरण 2x2+kx+3=0 के दो समान मूल हों, तो 'k' का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
द्विघात समीकरण 2x2+kx+3=0 के दो समान मूल होने के लिए, इसका विवर्तनक (discriminant) शून्य होना चाहिए। द्विघात समीकरण ax2+bx+c=0 के लिए विवर्तनक D=b2−4ac होता है।
यहाँ, a=2, b=k, और c=3 हैं। इसलिए,
[ D = k^2 - 4 \times 2 \times 3 = k^2 - 24 ]
चूंकि दो समान मूल होने के लिए विवर्तनक शून्य होना चाहिए, इसलिए:
[ k^2 - 24 = 0 ]
इससे हमें मिलता है:
[ k^2 = 24 ]
[ k = \pm \sqrt{24} ]
[ k = \pm 2\sqrt{6} ]
इस प्रकार, 'k' का मान ±26 है, जो विकल्प 1 के अनुसार सही है।
अब अन्य विकल्पों की गलतियों को समझते हैं:
-
±38: यदि हम k=±38 लेते हैं, तो k2=9×8=72 होगा, जो 24 के बराबर नहीं है। इसलिए यह विकल्प गलत है।
-
±56: यदि हम k=±56 लेते हैं, तो k2=25×6=150 होगा, जो 24 के बराबर नहीं है। इसलिए यह विकल्प गलत है।
-
±43: यदि हम k=±43 लेते हैं, तो k2=16×3=48 होगा, जो 24 के बराबर नहीं है। इसलिए यह विकल्प गलत है।
इस प्रकार, विकल्प 1, ±26, सही उत्तर है क्योंकि यह विवर्तनक को शून्य बनाता है, जो द्विघात समीकरण के दो समान मूल होने की शर्त को पूरा करता है।
Question 177
−5 + (−8) + (−11) + ....... + (−230) is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the problem of finding the sum of the series (-5 + (-8) + (-11) + \ldots + (-230)), we need to recognize that this is an arithmetic series. An arithmetic series is a sequence of numbers in which the difference between consecutive terms is constant.
Step-by-Step Explanation:
-
Identify the First Term and Common Difference:
- The first term ((a)) of the series is (-5).
- The common difference ((d)) is the difference between consecutive terms, which is (-8 - (-5) = -3).
-
Find the Last Term:
- The last term ((l)) of the series is given as (-230).
-
Determine the Number of Terms ((n)):
- The formula for the (n)-th term of an arithmetic sequence is given by:
[
a_n = a + (n-1) \cdot d
] - Setting (a_n = -230), we have:
[
-230 = -5 + (n-1) \cdot (-3)
]
[
-230 = -5 - 3(n-1)
]
[
-230 = -5 - 3n + 3
]
[
-230 = -2 - 3n
]
[
-228 = -3n
]
[
n = 76
]
- The formula for the (n)-th term of an arithmetic sequence is given by:
-
Calculate the Sum of the Series:
- The sum (S_n) of an arithmetic series is given by:
[
S_n = \frac{n}{2} \cdot (a + l)
] - Substituting the known values:
[
S_{76} = \frac{76}{2} \cdot (-5 + (-230))
]
[
S_{76} = 38 \cdot (-235)
]
[
S_{76} = 38 \cdot -235 = -8930
]
- The sum (S_n) of an arithmetic series is given by:
Conclusion:
- Option 1: -8930 is the correct answer because the calculated sum of the series is (-8930).
Explanation of Incorrect Options:
- Option 2: 8930 is incorrect because the sum of the series is negative, not positive.
- Option 3: 8989 is incorrect because it does not match the calculated sum of (-8930).
- Option 4: 8900 is incorrect because it is not the exact sum of the series, which is (-8930).
Thus, the correct answer is indeed Option 1: (-8930).
−5 + (−8) + (−11) + ....... + (−230) का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
इस प्रश्न में हमें एक श्रृंखला दी गई है: −5 + (−8) + (−11) + ....... + (−230)। यह एक अंकगणितीय प्रगति (Arithmetic Progression) है, जिसमें पहला पद (a = -5) है और प्रत्येक क्रमागत पद के बीच का अंतर (d = -3) है।
इस श्रृंखला का अंतिम पद (l = -230) है। हमें इस श्रृंखला के सभी पदों का योग ज्ञात करना है।
-
पदों की संख्या (n) ज्ञात करना:
अंतिम पद का सूत्र है:
[
l = a + (n-1) \times d
]
[
-230 = -5 + (n-1) \times (-3)
]
[
-230 + 5 = (n-1) \times (-3)
]
[
-225 = (n-1) \times (-3)
]
[
n-1 = 75
]
[
n = 76
]इस प्रकार, इस श्रृंखला में 76 पद हैं।
-
श्रृंखला का योग (S) ज्ञात करना:
अंकगणितीय प्रगति के योग का सूत्र है:
[
S = \frac{n}{2} \times (a + l)
]
[
S = \frac{76}{2} \times (-5 + (-230))
]
[
S = 38 \times (-235)
]
[
S = -8930
]
इस प्रकार, इस श्रृंखला का योग (-8930) है, जो विकल्प 1 के अनुसार सही उत्तर है।
अन्य विकल्प क्यों गलत हैं:
- विकल्प 2: 8930 - यह सकारात्मक संख्या है, जबकि सभी पद नकारात्मक हैं, इसलिए योग भी नकारात्मक होगा।
- विकल्प 3: 8989 - यह भी सकारात्मक संख्या है और गलत है क्योंकि योग नकारात्मक होना चाहिए।
- विकल्प 4: 8900 - यह भी गलत है क्योंकि यह सकारात्मक संख्या है और सही योग (-8930) है।
इस प्रकार, विकल्प 1 सही उत्तर है।
Question 178
If x−1x+1+x−2x+2=11x−1822x+30, then the value of ’x’ is :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the equation (\frac{x + 1}{x - 1} + \frac{x + 2}{x - 2} = \frac{22x + 30}{11x - 18}) and verify why Option 2, which is (x = -6), is the correct answer, we will follow these steps:
Step-by-Step Solution:
-
Combine the Left Side:
[
\frac{x + 1}{x - 1} + \frac{x + 2}{x - 2}
]
To combine these fractions, find a common denominator, which is ((x - 1)(x - 2)):
[
\frac{(x + 1)(x - 2) + (x + 2)(x - 1)}{(x - 1)(x - 2)}
] -
Expand and Simplify the Numerator:
[
(x + 1)(x - 2) = x^2 - 2x + x - 2 = x^2 - x - 2
]
[
(x + 2)(x - 1) = x^2 - x + 2x - 2 = x^2 + x - 2
]
Adding these results:
[
x^2 - x - 2 + x^2 + x - 2 = 2x^2 - 4
] -
Rewrite the Left Side:
[
\frac{2x^2 - 4}{(x - 1)(x - 2)}
] -
Equate to the Right Side:
[
\frac{2x^2 - 4}{(x - 1)(x - 2)} = \frac{22x + 30}{11x - 18}
] -
Cross-Multiply to Solve for x:
[
(2x^2 - 4)(11x - 18) = (22x + 30)(x - 1)(x - 2)
] -
Substitute (x = -6) into the Original Equation:
[
\frac{-6 + 1}{-6 - 1} + \frac{-6 + 2}{-6 - 2} = \frac{22(-6) + 30}{11(-6) - 18}
]
Simplifying each term:
[
\frac{-5}{-7} + \frac{-4}{-8} = \frac{-132 + 30}{-66 - 18}
]
[
\frac{5}{7} + \frac{1}{2} = \frac{-102}{-84}
]
[
\frac{5}{7} + \frac{1}{2} = \frac{51}{42}
]
[
\frac{10}{14} + \frac{7}{14} = \frac{51}{42}
]
[
\frac{17}{14} = \frac{51}{42}
]
Simplifying both sides confirms they are equal, verifying (x = -6) is correct.
Explanation for Other Options:
- Option 1 (x = 6): Substituting (x = 6) into the equation does not satisfy the equality, as the left and right sides do not equate.
- Option 3 (x = 5): Substituting (x = 5) into the equation also fails to satisfy the equality.
- Option 4 (x = -5): Similarly, substituting (x = -5) does not result in equal sides.
Thus, the only value of (x) that satisfies the equation is (-6), confirming that Option 2 is indeed the correct answer.
यदि x−1x+1+x−2x+2=11x−1822x+30 ,तो 'x' का मान है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
समाधान:
हमें दिए गए समीकरण को हल करना है:
[
\frac{x + 1}{x - 1} + \frac{x + 2}{x - 2} = \frac{22x + 30}{11x - 18}
]
हम सबसे पहले बाएँ पक्ष के दोनों भिन्नों का लघुत्तम समापवर्तक (LCM) लेंगे:
[
\frac{(x + 1)(x - 2) + (x + 2)(x - 1)}{(x - 1)(x - 2)}
]
इसका विस्तार करने पर हमें मिलता है:
[
\frac{(x^2 - 2x + x - 2) + (x^2 - x + 2x - 2)}{(x - 1)(x - 2)}
]
[
= \frac{x^2 - x - 2 + x^2 + x - 2}{(x - 1)(x - 2)}
]
[
= \frac{2x^2 - 4}{(x - 1)(x - 2)}
]
अब, हम इसे दिए गए दाएँ पक्ष के साथ तुलनात्मक करेंगे:
[
\frac{2x^2 - 4}{(x - 1)(x - 2)} = \frac{22x + 30}{11x - 18}
]
क्रॉस मल्टीप्लाई करने पर हमें मिलता है:
[
(2x^2 - 4)(11x - 18) = (22x + 30)(x - 1)(x - 2)
]
इस समीकरण को हल करने पर, हम 'x' के मान के लिए परीक्षण करेंगे। हमें यह सुनिश्चित करना है कि 'x' का मान समीकरण को संतुलित करता है।
जब हम विकल्प 2, अर्थात ( x = -6 ) का परीक्षण करते हैं:
बाएँ पक्ष:
[
\frac{-6 + 1}{-6 - 1} + \frac{-6 + 2}{-6 - 2} = \frac{-5}{-7} + \frac{-4}{-8}
]
[
= \frac{5}{7} + \frac{1}{2}
]
[
= \frac{10}{14} + \frac{7}{14} = \frac{17}{14}
]
दाएँ पक्ष:
[
\frac{22(-6) + 30}{11(-6) - 18} = \frac{-132 + 30}{-66 - 18}
]
[
= \frac{-102}{-84} = \frac{17}{14}
]
दोनों पक्ष समान हैं, इसलिए ( x = -6 ) सही उत्तर है।
अन्य विकल्पों के लिए:
- ( x = 6 ): यह मान समीकरण को संतुलित नहीं करता।
- ( x = 5 ): यह मान समीकरण को संतुलित नहीं करता।
- ( x = -5 ): यह मान समीकरण को संतुलित नहीं करता।
इसलिए, सही उत्तर विकल्प 2, अर्थात ( x = -6 ) है।
Question 179
Find the sum of first 24 terms of the list of numbers whose nth term is a_n = 3 + 2n :
Choose an answer to reveal your result and explanation.
Answer & Explanation
To find the sum of the first 24 terms of the sequence where the nth term is given by ( a_n = 3 + 2n ), we can use the formula for the sum of an arithmetic sequence. The formula for the sum ( S_n ) of the first ( n ) terms of an arithmetic sequence is:
[ S_n = \frac{n}{2} \times (a_1 + a_n) ]
where ( a_1 ) is the first term and ( a_n ) is the nth term.
Step-by-step Explanation:
-
Identify the first term (( a_1 )):
- For ( n = 1 ), the first term ( a_1 = 3 + 2(1) = 5 ).
-
Identify the 24th term (( a_{24} )):
- For ( n = 24 ), the 24th term ( a_{24} = 3 + 2(24) = 3 + 48 = 51 ).
-
Calculate the sum of the first 24 terms (( S_{24} )):
- Using the sum formula:
[
S_{24} = \frac{24}{2} \times (5 + 51) = 12 \times 56 = 672
]
- Using the sum formula:
Thus, the sum of the first 24 terms is 672, which corresponds to Option 3.
Explanation of why other options are incorrect:
-
Option 1 (680): This option is incorrect because the calculation of the sum using the arithmetic sequence formula results in 672, not 680. The arithmetic sequence formula has been applied correctly, and 680 does not match the calculated sum.
-
Option 2 (670): This option is incorrect for the same reason as above. The correct sum, as calculated, is 672. The value 670 does not match the result obtained from the formula.
-
Option 4 (675): This option is also incorrect. The calculated sum using the arithmetic sequence formula is 672, and 675 does not match this result.
In conclusion, the correct answer is Option 3 (672), as it accurately reflects the sum of the first 24 terms of the given sequence.
संख्याओं की सूची के प्रथम 24 पदों का योग ज्ञात कीजिए, जिसका nवाँ पद a_n = 3 + 2n से दिया जाता है :
Choose an answer to reveal your result and explanation.
Answer & Explanation
प्रश्न: संख्याओं की सूची के प्रथम 24 पदों का योग ज्ञात कीजिए, जिसका nवाँ पद ( a_n = 3 + 2n ) से दिया जाता है।
समाधान:
-
प्रथम 24 पदों का योग ज्ञात करना:
दिए गए अनुक्रम का nवाँ पद ( a_n = 3 + 2n ) है। हमें पहले 24 पदों का योग ज्ञात करना है।
[
a_1 = 3 + 2 \times 1 = 5
]
[
a_2 = 3 + 2 \times 2 = 7
]
[
a_3 = 3 + 2 \times 3 = 9
]
[
\ldots
]
[
a_{24} = 3 + 2 \times 24 = 51
]यह एक अंकगणितीय अनुक्रम है, जहाँ प्रथम पद ( a_1 = 5 ) है और अंतर ( d = 2 ) है।
-
अंकगणितीय अनुक्रम के योग का सूत्र:
अंकगणितीय अनुक्रम के पहले n पदों का योग ( S_n ) का सूत्र है:
[
S_n = \frac{n}{2} \times (a_1 + a_n)
]यहाँ ( n = 24 ), ( a_1 = 5 ), और ( a_{24} = 51 ) है।
[
S_{24} = \frac{24}{2} \times (5 + 51)
]
[
S_{24} = 12 \times 56
]
[
S_{24} = 672
] -
सही विकल्प का चयन:
इस प्रकार, पहले 24 पदों का योग 672 है। इसलिए, सही उत्तर विकल्प 3 है।
-
अन्य विकल्प क्यों गलत हैं:
- विकल्प 1 (680): यह गलत है क्योंकि गणना के अनुसार योग 672 है, न कि 680।
- विकल्प 2 (670): यह गलत है क्योंकि गणना के अनुसार योग 672 है, न कि 670।
- विकल्प 4 (675): यह गलत है क्योंकि गणना के अनुसार योग 672 है, न कि 675।
इस प्रकार, दिए गए प्रश्न के अनुसार सही उत्तर विकल्प 3 (672) है।
Question 180
The solution of following system of linear equation is :
7x+11y=0
3x−5y=0
Choose an answer to reveal your result and explanation.
Answer & Explanation
To solve the given system of linear equations:
- (\sqrt{7}x + \sqrt{11}y = 0)
- (\sqrt{3}x - \sqrt{5}y = 0)
we need to find the values of (x) and (y) that satisfy both equations simultaneously.
Explanation for Option 4:
Option 4 states that (x = 0) and (y = 0). Let's verify this solution:
-
Substitute (x = 0) and (y = 0) into the first equation:
[
\sqrt{7}(0) + \sqrt{11}(0) = 0
]
This simplifies to (0 = 0), which is true. -
Substitute (x = 0) and (y = 0) into the second equation:
[
\sqrt{3}(0) - \sqrt{5}(0) = 0
]
This also simplifies to (0 = 0), which is true.
Since both equations are satisfied with (x = 0) and (y = 0), Option 4 is indeed the correct solution.
Explanation for why other options are incorrect:
-
Option 1: (x = \frac{-\sqrt{11}}{7}, y = \frac{-\sqrt{11}}{7})
Substitute these values into the first equation:
[
\sqrt{7}\left(\frac{-\sqrt{11}}{7}\right) + \sqrt{11}\left(\frac{-\sqrt{11}}{7}\right) = 0
]
This simplifies to:
[
\frac{-\sqrt{77}}{7} - \frac{11}{7} \neq 0
]
Therefore, Option 1 does not satisfy the first equation. -
Option 2: (x = \frac{\sqrt{11}}{7}, y = \frac{\sqrt{11}}{7})
Substitute these values into the first equation:
[
\sqrt{7}\left(\frac{\sqrt{11}}{7}\right) + \sqrt{11}\left(\frac{\sqrt{11}}{7}\right) = 0
]
This simplifies to:
[
\frac{\sqrt{77}}{7} + \frac{11}{7} \neq 0
]
Therefore, Option 2 does not satisfy the first equation. -
Option 3: (x = 0, y = 1)
Substitute these values into the first equation:
[
\sqrt{7}(0) + \sqrt{11}(1) = 0
]
This simplifies to:
[
\sqrt{11} \neq 0
]
Therefore, Option 3 does not satisfy the first equation.
In conclusion, only Option 4, where (x = 0) and (y = 0), satisfies both equations, making it the correct solution.
निम्नलिखित रेखिक समीकरण का हल है :
7x+11y=0
3x−5y=0
Choose an answer to reveal your result and explanation.
Answer & Explanation
समाधान के लिए हमें दिए गए रेखिक समीकरणों को हल करना होगा:
- 7x+11y=0
- 3x−5y=0
इन समीकरणों को हल करने के लिए, हम देखते हैं कि दोनों समीकरणों में x और y के गुणांक अलग-अलग हैं। इन समीकरणों का हल निकालने के लिए, हम सबसे पहले यह मान सकते हैं कि x=0 और y=0 हो सकता है।
यदि हम x=0 और y=0 रखते हैं, तो:
- पहले समीकरण में: 7(0)+11(0)=0, जो कि सही है।
- दूसरे समीकरण में: 3(0)−5(0)=0, जो कि सही है।
इस प्रकार, x=0 और y=0 दोनों समीकरणों को संतुष्ट करते हैं। इसलिए, विकल्प 4 सही है।
अब हम अन्य विकल्पों को गलत साबित करते हैं:
-
विकल्प 1: x=7−11,y=7−11
यदि हम इन मूल्यों को पहले समीकरण में रखते हैं, तो 7(7−11)+11(7−11)=0 होगा। इसलिए यह विकल्प गलत है।
-
विकल्प 2: x=711,y=711
यदि हम इन मूल्यों को पहले समीकरण में रखते हैं, तो 7(711)+11(711)=0 होगा। इसलिए यह विकल्प गलत है।
-
विकल्प 3: x=0,y=1
यदि हम इन मूल्यों को पहले समीकरण में रखते हैं, तो 7(0)+11(1)=0 होगा। इसलिए यह विकल्प गलत है।
इस प्रकार, विकल्प 4: x=0,y=0 ही सही उत्तर है।