Question
Easy
If a number is of the form 810├Ч97├Ч78, then the number of prime factors of the given number is :
1
36
2
46
3
52
4
55
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 1
Chapter: Number Operations
Topic: Prime Factorization
Correct Answer
Option B
Explanation
To determine the number of prime factors of the number in the form \(810 \times 97 \times 78\), we need to factorize each component into its prime factors and then count the total number of prime factors. 1. Factorize 810: - 810 is divisible by 2: \(810 \div 2 = 405\) - 405 is divisible by 3: \(405 \div 3 = 135\) - 135 is divisible by 3: \(135 \divтАжRead More
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