Question
Easy
If $y + \frac{1}{z} = 1 \quad \text{and} \quad x + \frac{1}{y}$ = 1, then the value of xyz is :
1
-1
2
1
3
2
4
can not be determined
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 1
Chapter: Algebra
Topic: Equations
Correct Answer
Option C
Explanation
To solve the problem and justify why Option 3 is correct, we need to find the value of \(xyz\) given the equations: 1. \(y + \frac{1}{z} = 1\) 2. \(x + \frac{1}{y} = 1\) Let's solve these equations step by step: ### Step 1: Solve for \(z\) in terms of \(y\) From the first equation: \[ y + \frac{1}{z} = 1 \] Rearrange to solve for \(\frac{1}{z}\): \[ \frac{1}{z} =тАжRead More
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