Question
Easy

Match List-I and List-II and choose the correct answer from the codes given below the lists : List-I : $\qquad$$\qquad$ $\qquad$ $\qquad$ $\qquad$ List-II $(A.) N_2O_3 \rightleftharpoons NO + NO_2\quad$ : (i) $k_p = k_c(RT)$ $(B.) 2NH_3 \rightleftharpoons N_2 + 3H_2\quad$ : (ii) $k_c = k_p(RT)$ $(C.) 2SO_2 + O_2 \rightleftharpoons 2SO_3\quad$ : (iii) $k_c = k_p$ $(D.) N_2 + O_2 \rightleftharpoons 2NO\qquad$ (iv) k_p = $k_c(RT)^2$<br $\text{Code :}$

1
(A)(i); (B)(iv); (C)(ii); (D)(iii)
2
(A)(i); (B)(ii); (C)(iii); (D)(iv)
3
(A)(iv); (B)(iii); (C)(i); (D)(ii)
4
(A)(iii); (B)(iv); (C)(ii); (D)(i)
Question Details
Time to Solve: 12
Exam: HTET
Level/Paper: Level 2
Chapter: Matter in Our Surroundings
Topic: Changes of State
Correct Answer
Option A
Explanation

To justify why Option 1 is the correct answer, we need to analyze the relationship between the equilibrium constants \( k_c \) and \( k_p \) for each reaction given in List-I and List-II. The relationship between \( k_c \) and \( k_p \) is determined by the change in the number of moles of gas (\(\Delta n\)) in the reaction, where: \[ k_p = k_c(RT)^{\Delta n} \] Let's evaluate…Read More